![homework and exercises - Why does P = $\rho$gh seem to contradict equal accelerations of fluids in a closed U tube? - Physics Stack Exchange homework and exercises - Why does P = $\rho$gh seem to contradict equal accelerations of fluids in a closed U tube? - Physics Stack Exchange](https://i.stack.imgur.com/QGf8x.jpg)
homework and exercises - Why does P = $\rho$gh seem to contradict equal accelerations of fluids in a closed U tube? - Physics Stack Exchange
![As shown in the diagram, water will be filled up to a height of $h$ in a beaker of radius $R$. The density of water is $\\rho $, the surface tension of As shown in the diagram, water will be filled up to a height of $h$ in a beaker of radius $R$. The density of water is $\\rho $, the surface tension of](https://www.vedantu.com/question-sets/a0266023-b6fc-4df2-8f6a-4e2d6cdfec603987047058174668466.png)
As shown in the diagram, water will be filled up to a height of $h$ in a beaker of radius $R$. The density of water is $\\rho $, the surface tension of
![Which equation are dimensionally valid out of following equations (i) Pressure P= rho gh where rho= density of matter, g= acceleration due to gravity. H= height. (ii) F.S =(1)/(2) mv^(2)-(1)/(2) mv(0)^(2) where Which equation are dimensionally valid out of following equations (i) Pressure P= rho gh where rho= density of matter, g= acceleration due to gravity. H= height. (ii) F.S =(1)/(2) mv^(2)-(1)/(2) mv(0)^(2) where](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/639276636_web.png)
Which equation are dimensionally valid out of following equations (i) Pressure P= rho gh where rho= density of matter, g= acceleration due to gravity. H= height. (ii) F.S =(1)/(2) mv^(2)-(1)/(2) mv(0)^(2) where
![Fluids and Elasticity Chapter 15. Density ( ) = mass/volume Rho ( ) – Greek letter for density Units - kg/m 3 Specific Gravity = Density of substance. - ppt download Fluids and Elasticity Chapter 15. Density ( ) = mass/volume Rho ( ) – Greek letter for density Units - kg/m 3 Specific Gravity = Density of substance. - ppt download](https://images.slideplayer.com/21/6244585/slides/slide_9.jpg)
Fluids and Elasticity Chapter 15. Density ( ) = mass/volume Rho ( ) – Greek letter for density Units - kg/m 3 Specific Gravity = Density of substance. - ppt download
![A leakage begins in the water tank at position P as shown in the figure. The initial gauge pressure at P was $5 \\times {10^5}N\/{m^2}$ .if the density of water is $1000kg\/{m^3}$ A leakage begins in the water tank at position P as shown in the figure. The initial gauge pressure at P was $5 \\times {10^5}N\/{m^2}$ .if the density of water is $1000kg\/{m^3}$](https://www.vedantu.com/question-sets/7035f857-3927-49bb-8864-639f72a6a78a5417170476163578524.png)
A leakage begins in the water tank at position P as shown in the figure. The initial gauge pressure at P was $5 \\times {10^5}N\/{m^2}$ .if the density of water is $1000kg\/{m^3}$
![Fluids and Elasticity Chapter 15. Density ( ) = mass/volume Rho ( ) – Greek letter for density Units - kg/m 3 Specific Gravity = Density of substance. - ppt download Fluids and Elasticity Chapter 15. Density ( ) = mass/volume Rho ( ) – Greek letter for density Units - kg/m 3 Specific Gravity = Density of substance. - ppt download](https://images.slideplayer.com/21/6244585/slides/slide_23.jpg)
Fluids and Elasticity Chapter 15. Density ( ) = mass/volume Rho ( ) – Greek letter for density Units - kg/m 3 Specific Gravity = Density of substance. - ppt download
Is the equation [math]p=\rho gh[/math] the definition of hydrostatic pressure or just the equation from where we calculate it? - Quora
![SOLVED: The pressure in fluid depends on both the density and the depth (h): P = pgh Using these relationships determine the atmospheric pressure at the following ocations Assume that atmospheric pressure SOLVED: The pressure in fluid depends on both the density and the depth (h): P = pgh Using these relationships determine the atmospheric pressure at the following ocations Assume that atmospheric pressure](https://cdn.numerade.com/ask_previews/168036cf-4908-49f4-bdd9-d0a7769a4c72_large.jpg)
SOLVED: The pressure in fluid depends on both the density and the depth (h): P = pgh Using these relationships determine the atmospheric pressure at the following ocations Assume that atmospheric pressure
![Fluids and Elasticity Chapter 15. Density ( ) = mass/volume Rho ( ) – Greek letter for density Units - kg/m 3 Specific Gravity = Density of substance. - ppt download Fluids and Elasticity Chapter 15. Density ( ) = mass/volume Rho ( ) – Greek letter for density Units - kg/m 3 Specific Gravity = Density of substance. - ppt download](https://images.slideplayer.com/21/6244585/slides/slide_14.jpg)